Fulton 2.1
Posted on November 15, 20172.1.* Show the map that associates each to a polynomial function in
is a ring homomorphism with kernel
Clearly the map is a ring homorphism. Suppose such that
is the zero function in
Then
for all
Thus
Similarly, if
then
is the zero function.
2.2.* Let be a variety. A subvariety of
is a variety
that is contained in
Show that there is a natural one-to-one correspondence between algebraic subsets (resp. subvarieties, resp. points) of
and radical ideals (resp. prime ideals, resp. maximal ideals) of
Recall there is a one to one correspondence between radical, prime, and maximal ideals in
and radical, prime, and maximal ideals
in
such that
Observe that that
is an algebraic subset, subvariety, or point of
if and only if
is a radical, prime, or maximal ideal in
with
2.3.* Let be a subvariety of a variety
and let
be the ideal of
corresponding to
(a) Show that every polynomial function on restricts to a polynomial function on
Suppose is a polynomial function. Then there exists
such that
for all
Since
is polynomial as well. In terms of coordinate rings, this restriction map defines a homomorphism
where
(b) Show the map defined in (a) is surjective with kernel
so
Let and
be the natural homomorphisms. Since
are surjective and
by descending to the quotient (Lemma 1.1) there exists a surjective homomorphism
with
Moreover,
So
2.4.* Let be a nonempty variety. Show the following are equivalent: (1)
is a point; (2)
; (3)
(1) (2). Suppose
Then
Therefore
Conversely, suppose
Then
is maximal. Since
is algebraically closed,
Thus
is a point.
(2) (3). Clearly if
then
Conversely, suppose
Let
be the field of fractions for
By Lemma 2.1,
is finite field extension of
Since
is algebraically closed, by Problem 1.48,
Thus
2.5. Let be an irreducible polynomial in
and suppose
is monic in
:
with
Let
Show that the natural homomorphism from
to
is one-to-one, so that
may be regarded as a subring of
; show that the residues
generate
over
as a module.
Observe that if then
is constant,
and
is the trivial ring. Thus suppose
Note that the natural homomorphism maps
Suppose
such that
that is,
Observe that
since
so
and
So the map is one-to-one.
Let Observe we have
Hence for any
for some
Thus
generate
over
as a module.