Fulton 2.1
Posted on November 15, 20172.1.* Show the map that associates each to a polynomial function in is a ring homomorphism with kernel
Clearly the map is a ring homorphism. Suppose such that is the zero function in Then for all Thus Similarly, if then is the zero function.
2.2.* Let be a variety. A subvariety of is a variety that is contained in Show that there is a natural one-to-one correspondence between algebraic subsets (resp. subvarieties, resp. points) of and radical ideals (resp. prime ideals, resp. maximal ideals) of
Recall there is a one to one correspondence between radical, prime, and maximal ideals in and radical, prime, and maximal ideals in such that Observe that that is an algebraic subset, subvariety, or point of if and only if is a radical, prime, or maximal ideal in with
2.3.* Let be a subvariety of a variety and let be the ideal of corresponding to
(a) Show that every polynomial function on restricts to a polynomial function on
Suppose is a polynomial function. Then there exists such that for all Since is polynomial as well. In terms of coordinate rings, this restriction map defines a homomorphism where
(b) Show the map defined in (a) is surjective with kernel so
Let and be the natural homomorphisms. Since are surjective and by descending to the quotient (Lemma 1.1) there exists a surjective homomorphism with Moreover, So
2.4.* Let be a nonempty variety. Show the following are equivalent: (1) is a point; (2) ; (3)
(1) (2). Suppose Then Therefore Conversely, suppose Then is maximal. Since is algebraically closed, Thus is a point.
(2) (3). Clearly if then Conversely, suppose Let be the field of fractions for By Lemma 2.1, is finite field extension of Since is algebraically closed, by Problem 1.48, Thus
2.5. Let be an irreducible polynomial in and suppose is monic in : with Let Show that the natural homomorphism from to is one-to-one, so that may be regarded as a subring of ; show that the residues generate over as a module.
Observe that if then is constant, and is the trivial ring. Thus suppose
Note that the natural homomorphism maps Suppose such that that is, Observe that since so and So the map is one-to-one.
Let Observe we have Hence for any for some Thus generate over as a module.